Reversing - 021

备注

created by || 0xH3rshel

⏲️ Release Date // 2022-09-06

💀 Solvers // 16

🧩 Type // rev

反编译

int __fastcall main(int argc, const char **argv, const char **envp)
{
  char s[264]; // [rsp+0h] [rbp-120h] BYREF
  const char *v5; // [rsp+108h] [rbp-18h]
  int i; // [rsp+114h] [rbp-Ch]
  int v7; // [rsp+118h] [rbp-8h]
  int v8; // [rsp+11Ch] [rbp-4h]

  v5 = "$uperZecretP4zz";
  v8 = 0;
  v7 = 1;
  printf("Enter passwd: ");
  __isoc99_scanf("%s", s);
  if ( strlen(s) == 6 )
  {
    if ( s[0] == 80 )
    {
      for ( i = 1; i <= 5; ++i )
      {
        v8 += s[i] - 48;
        v7 *= s[i] - 48;
      }
      if ( v8 == 24 && v7 == 2048 )
      {
        if ( s[1] == 56 )
          printf("Correct");
        else
          printf("really close");
      }
      else
      {
        printf("Close");
      }
    }
    else
    {
      printf("Almost");
    }
  }
  else
  {
    printf("Incorrect");
  }
  return 0;
}

Python脚本进行爆破

import string
import itertools as its


def check(ins):
    v8 = 0
    v7 = 1
    for i in range(1, 6):
        v8 += ord(ins[i]) - 48
        v7 *= ord(ins[i]) - 48
    if v8 == 24 and v7 == 2048:
        return True


s = ""

s += chr(80)
s += chr(56)

dic = string.digits + string.ascii_letters
r = its.product(dic, repeat=4)

for i in r:
    word = "".join(i)
    tmp = s + word
    if check(tmp):
        print(tmp)

# P84444